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Cambridge IGCSE Maths (0580) · Topic 2: Algebra and graphs · 2.9

Cambridge IGCSE Maths 0580 Real-Life Graphs Questions

Real-Life Graphs questions with worked answers for Cambridge IGCSE Mathematics (0580). Each question says whether it is Core or Extended and whether it is for a calculator or non-calculator paper. Try each one before you open the answer.

Practise real-life graphs →Real-Life Graphs notes

What the syllabus asks

Summarised in our own words: check the exact wording in the official 0580 syllabus.

Real-Life Graphs questions: Core

For everyone: Core students (Papers 1 and 3) and Extended students (Papers 2 and 4).

Question 1 Core non-calculator · easy

A conversion graph is a straight line through \((0, 0)\) and \((50, 80)\). It changes miles (across) to kilometres (up).
Use it to change
(a) \(25\) miles to kilometres
(b) \(120\) kilometres to miles.

Show the worked answer
  1. \(50\) miles \(= 80\) km, so \(1\) mile \(= 1.6\) km.
  2. (a) \(25 \times 1.6 = 40\) km
  3. (b) \(120 \div 1.6 = 75\) miles

Answer: (a) \(40\) km (b) \(75\) miles

Question 2 Core non-calculator · easy

Sam's walk is shown on a distance-time graph made of straight lines joining \((0, 0)\), \((20, 1.5)\), \((35, 1.5)\) and \((60, 0)\). Time is in minutes and distance from home in kilometres.
(a) For how long did Sam stop?
(b) Work out Sam's speed on the way home in km/h.

Show the worked answer
  1. (a) The graph is flat from \(20\) to \(35\) minutes: \(15\) minutes.
  2. (b) Home is \(1.5\) km in \(25\) minutes. \(25\) minutes \(= \frac{25}{60}\) h, so speed \(= 1.5 \div \frac{25}{60} = 3.6\) km/h.

Answer: (a) \(15\) minutes (b) \(3.6\) km/h

Question 3 Core calculator · easy · 2 marks

The graph of a taxi fare against distance is a straight line from \((0, 3)\) to \((10, 21)\), where the distance is in km and the fare is in dollars.

(a) Write down the fixed charge.

(b) Work out the charge per kilometre.

Show the answer and mark scheme
  • B1 (a) 3
  • B1 (b) 1.80

Answer: (a) \(\$3\) (b) \(\$1.80\)

Question 4 Core non-calculator · medium

A cyclist's journey is shown by straight lines joining \((0, 0)\), \((30, 12)\), \((45, 12)\) and \((75, 30)\), with time in minutes and distance in kilometres.
Work out the cyclist's average speed for the whole journey, in km/h.

Show the worked answer
  1. Total distance \(30\) km in \(75\) minutes \(= 1.25\) hours.
  2. \(30 \div 1.25 = 24\) km/h

Answer: \(24\) km/h

Question 5 Core non-calculator · medium · 2 marks

A distance–time graph shows that a car travels 120 km between 09 00 and 10 30. Work out its average speed.

Show the answer and mark scheme
  • M1 120 ÷ 1.5
  • A1 80 km/h

Answer: \(80\) km/h

Question 6 Core calculator · medium · 2 marks

A conversion graph between miles and kilometres is a straight line through \((0, 0)\) and \((5, 8)\), with miles on the horizontal axis.

(a) Change 35 miles into kilometres.

(b) Change 100 km into miles.

Show the answer and mark scheme
  • B1 (a) 56
  • B1 (b) 62.5

Answer: (a) \(56\) km (b) \(62.5\) miles

Real-Life Graphs questions: Extended

Extended content, for Papers 2 and 4. Core students can skip these.

Question 7 Extended non-calculator · medium

A car speeds up at a constant rate from rest to \(20\) m/s in \(8\) seconds.
Work out its acceleration.

Show the worked answer
  1. Acceleration \(=\) gradient of the speed-time graph \(= \frac{20 - 0}{8} = 2.5\) m/s².

Answer: \(2.5\) m/s²

Question 8 Extended non-calculator · medium

A speed-time graph is made of straight lines joining \((0, 0)\), \((10, 15)\), \((40, 15)\) and \((50, 0)\), with time in seconds and speed in m/s.
Work out the total distance travelled.

Show the worked answer
  1. Distance \(=\) area under the graph, a trapezium with parallel sides \(30\) s and \(50\) s and height \(15\) m/s.
  2. \(\frac{1}{2}(30 + 50) \times 15 = 600\) m

Answer: \(600\) m

Question 9 Extended non-calculator · hard

A speed-time graph is made of straight lines joining \((0, 4)\), \((6, 16)\) and \((16, 16)\), with time in seconds and speed in m/s.
(a) Work out the acceleration in the first \(6\) seconds.
(b) Work out the distance travelled in the \(16\) seconds.

Show the worked answer
  1. (a) \(\frac{16 - 4}{6} = 2\) m/s²
  2. (b) First \(6\) s: trapezium \(\frac{1}{2}(4 + 16) \times 6 = 60\) m. Next \(10\) s: \(16 \times 10 = 160\) m.
  3. Total \(= 220\) m.

Answer: (a) \(2\) m/s² (b) \(220\) m

Every question on this page is original, written for IGCSE Math Revision rather than taken from Cambridge papers, and each answer was re-solved independently before publishing. Questions with a mark scheme come from our 0580 practice bank (M method, A accuracy, B independent marks).

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Questions students ask

Which Cambridge 0580 papers can test real-life graphs?

Real-Life Graphs is on both tiers (syllabus 2.9), so it can come up on Core Papers 1 (non-calculator) and 3 (calculator), and Extended Papers 2 (non-calculator) and 4 (calculator). Extended candidates also need the Extended parts listed on this page. Half of each tier's marks are on a non-calculator paper, so practise the non-calculator questions without one.

Are these Cambridge past-paper questions?

No. Every question here was written for IGCSE Math Revision in the style of the 0580 papers, and each answer was checked independently before publishing. For real exam practice, use the Cambridge past papers linked from our 0580 past papers page.

Where can I practise more real-life graphs questions?

In the 0580 practice for topic 2 (Algebra and graphs), where every question is marked and tagged Core or Extended. Practice is part of the IGCSE plan, with a free preview; the questions on this page are free.

More algebra and graphs questions