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Interior angles of a polygon formula: (n − 2) × 180°

The interior angles of a polygon formula is sum of interior angles = (n − 2) × 180°.

What each letter means

When to use it

To find the angle sum of any polygon, or each interior angle of a regular polygon: (n − 2) × 180° ÷ n.

Worked examples

1. Find the size of each interior angle of a regular 12-sided polygon.

  1. Sum \(=(12-2)\times180^\circ=1800^\circ\)
  2. Each angle \(=1800^\circ\div12\)

Answer: \(150^\circ\)

2. Each exterior angle of a regular polygon is \(24^\circ\). How many sides does it have?

  1. \(n=360^\circ\div24^\circ\)

Answer: 15 sides

Common mistake

Using n × 180°. A polygon with n sides splits into n − 2 triangles from one vertex.

On your course

CourseIn the exam
Edexcel 4MA1 (Higher)Not given: learn it
Cambridge 0580Not given: learn it

From our own IGCSE Maths formula sheets, in our words. Official: Pearson's 4MA1 specification (PDF, Appendix 5) · Cambridge's 0580 syllabus (PDF).

Practise and revise

Interior angles of a polygon formula card: sum of interior angles = (n − 2) × 180°. IGCSE Math Revision
Interior angles of a polygon formula card. Download the card (PNG) to save or print it.

Questions

What is the interior angles of a polygon formula?

The interior angles of a polygon formula is sum of interior angles = (n − 2) × 180°. n: the number of sides.

Is the interior angles of a polygon given in the exam?

Edexcel 4MA1 (Higher): not given: learn it. Cambridge 0580: not given: learn it. This comes from our own IGCSE Maths formula sheets; your teacher has the official booklet.

What do the exterior angles of a polygon add up to?

360°, for any convex polygon. Each exterior angle of a regular polygon is 360° ÷ n.

Our own wording, examples and card, checked by IGCSE Math Revision. Not produced or endorsed by Pearson Edexcel.