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Edexcel IGCSE Maths (4MA1) · Unit 7: Vectors & Proof

Edexcel IGCSE 4MA1 Vectors: Exam Questions and Answers

Vectors questions with full solutions for Pearson Edexcel International GCSE Mathematics A (4MA1), Higher tier. Read the 3 worked examples first, then try the 8 exam-style questions yourself and check your working against the mark scheme.

Practise vectors in Unit 7 →Vectors revision notes

Try it first

1 of 5

  1. Question 1 of 5
  2. Question 2 of 5
  3. Question 3 of 5
  4. Question 4 of 5
  5. Question 5 of 5

Start with one question on vectors. Stuck? Take a hint. No sign-in needed.

Find the magnitude of (6−8).
Choose your answer · keys 1–4

What this topic covers

Vectors worked examples

Worked example 1: Column vectors

a=(2−5). Find 3a and the magnitude of (5−12).

Solution

3 steps · 1 to fill in
Tip: Magnitude uses Pythagoras.

Worked example 2: Vector arithmetic

a=(41), b=(−23). Find a−2b.

Solution

3 steps
Tip: Subtracting a negative adds.

Worked example 3: Midpoint vector

OA→=a, OB→=b and M is the midpoint of AB. Find OM→.

Triangle OAB with OA = a and OB = b; M is the midpoint of AB and OM is dashed

Solution

3 steps
Tip: Travel along known vectors from O to M.

Vectors exam-style questions

Try each question before you open the answer (one has its full worked solution open). The mark schemes use Edexcel-style marks: M for method, A for accuracy (after the method mark), B for an independent result.

Question 1 · easy · 2 marks

a=(3−2) and b=(−15). Write 2a−3b as a column vector.

Show the answer and mark scheme
  • M1 (6, −4) or (−3, 15) seen as column vectors
  • A1 (9, −19) as a column vector

Answer: (9−19)

Question 2 · easy · 2 marks

AB→=3a−6b and CD→=−a+2b. Show that AB is parallel to CD.

Show the answer and mark scheme
  • B1 AB = −3(−a + 2b) = −3 CD
  • B1 one vector is a multiple of the other, so AB is parallel to CD

Answer: AB→=−3CD→, so AB is parallel to CD (shown)

Question 3 · medium · 3 marks

(a) Find the magnitude of the vector p=(5−12). (b) The vector q=(k6) has magnitude 10, and k is negative. Find the value of k.

Show the answer and mark scheme
  • B1 13
  • M1 k² + 6² = 10²
  • A1 k = −8

Answer: (a) 13 (b) k=−8

Question 4 · medium · 3 marks

OA→=a and OB→=b. P lies on AB with AP:PB=1:3. Find OP→ in terms of a and b. Give your answer in its simplest form.

Show the answer and mark scheme
  • M1 AB = b − a
  • M1 OP = a + ¼(b − a)
  • A1 ¾a + ¼b oe

Answer: 34a+14b

Question 5 · medium · 3 marks

OP→=2a+b, OQ→=5a+3b and OR→=11a+7b. Prove that P, Q and R are collinear.

Full worked solution Free, no sign-in

  • M1 PQ = 3a + 2b or QR = 6a + 4b
  • M1 both PQ and QR (or PR = 9a + 6b)
  • A1 QR = 2PQ, parallel with the common point Q, so collinear

Answer: QR→=6a+4b=2PQ→, with the common point Q (proved)

Every question here has a full worked solution. See them all →

Question 6 · hard · 4 marks

OABC is a parallelogram with OA→=a and OC→=c. M is the midpoint of AB, and N is the point on OC with ON:NC=1:3. Find NM→ in terms of a and c. Give your answer in its simplest form.

Show the answer and mark scheme
  • B1 OM = a + ½c
  • B1 ON = ¼c
  • M1 NM = NO + OM = −¼c + a + ½c
  • A1 a + ¼c

Answer: a+14c

Question 7 · hard · 4 marks

OA→=4a and OB→=4b. P is the midpoint of OA. Q lies on AB with AQ:QB=3:1. R lies on OB extended so that OR→=6b. (a) Find PQ→ in terms of a and b. (b) Prove that P, Q and R lie on a straight line.

Show the answer and mark scheme
  • M1 OQ = 4a + ¾(4b − 4a) = a + 3b
  • A1 PQ = −a + 3b
  • M1 PR = −2a + 6b
  • A1 PR = 2PQ, so PQ and PR are parallel and share the point P: P, Q, R are collinear

Answer: (a) −a+3b (b) PR→=−2a+6b=2PQ→, parallel with the common point P, so collinear (proved)

Question 8 · very hard · 6 marks

OABC is a parallelogram with OA→=a and OC→=c. N is the midpoint of AB. Y is the point on CN with CY:YN=2:1. (a) Find CN→ in terms of a and c. (b) Prove that Y lies on the diagonal OB, and find the ratio OY:YB.

Show the answer and mark scheme
  • B1 ON = a + ½c (or AN = ½c)
  • M1 CN = −c + a + ½c
  • A1 CN = a − ½c
  • M1 OY = c + ⅔(a − ½c)
  • A1 OY = ⅔a + ⅔c
  • A1 OB = a + c, so OY = ⅔ OB: a multiple of OB with O common, so Y lies on OB; OY : YB = 2 : 1

Answer: (a) a−12c (b) OY→=23a+23c=23OB→, so Y lies on OB (proved); OY:YB=2:1

Every question and worked example here is original, written for IGCSE Math Revision rather than copied from Pearson papers, and each answer was re-solved independently before publishing.

Revise vectors for the exam

Questions students ask

Which Edexcel IGCSE Maths papers test vectors?

Either Higher tier paper, 1H or 2H, can test vectors: both cover the whole Pearson Edexcel International GCSE Mathematics A (4MA1) specification and both allow a calculator. Show your method, because most marks are for working.

Where can I practise more vectors questions?

In the IGCSE student hub: Unit 7 (Vectors & Proof) has more exam-style questions on this topic, each with a mark scheme. Practice starts with a 7-day free trial; the worked examples and questions on this page are free.

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