Edexcel 4MA1Cambridge 0580
IGCSE Math Revision Questions by topic Revision notes Past papers Student hub

Edexcel IGCSE Maths A (4MA1) · Foundation tier · Questions

IGCSE Maths 4MA1 Foundation Statistics and Probability Questions

9 original exam-style questions on statistics and probability for the Foundation tier, three for each sub-topic, from easier to harder. Try each one, then open the mark scheme and the worked solution. The marks are Edexcel style: M for method, A for accuracy, B for an independent result.

More statistics and probability practice →Statistics and Probability notes

6.1 Graphical representation of data questions

Revise it first: Graphical representation of data notes and worked example.

Question 1 · 2 marks · grade 1

In a pictogram, one symbol represents 4 cars.

(a) How many symbols are needed to show 18 cars?

(b) How many cars are shown by \(2\frac{3}{4}\) symbols?

Show the answer, mark scheme and worked solution
  • B1 (a) 4.5 (4½ symbols)
  • B1 (b) 11
  1. (a) 18 ÷ 4 = 4.5 symbols.
  2. (b) 2.75 × 4 = 11 cars.

Answer: (a) \(4\frac{1}{2}\) symbols (b) \(11\) cars

Question 2 · 3 marks · grade 4

120 people each chose one activity: swim, run or cycle. 70 of them were adults. 15 children chose cycle and 20 children chose swim. 25 adults chose run. 45 people in total chose swim.

How many adults chose cycle?

Show the answer, mark scheme and worked solution
  • M1 for children = 50 or adults who swim = 45 − 20 = 25
  • M1 for 70 − 25 − 25
  • A1 20
  1. Adults who chose swim: 45 − 20 = 25.
  2. Adults: 70 = 25 (swim) + 25 (run) + cycle, so cycle = 20.

Answer: \(20\)

Question 3 · 4 marks · grade 5

A pie chart shows people's favourite pets. The angles are: cats 150°, dogs 120°, fish \(x°\) and other \(2x°\). 24 people chose dogs.

(a) Work out the value of \(x\).

(b) How many people chose 'other'?

Show the answer, mark scheme and worked solution
  • M1 (a) for 150 + 120 + 3x = 360
  • A1 (a) 30
  • M1 (b) for total = 24 × 360/120 (= 72) or 1° = 0.2 people
  • A1 (b) 12
  1. (a) 270 + 3x = 360, so x = 30.
  2. (b) 120° is 24 people, so 360° is 72 people.
  3. 'Other' is 60°: 60/360 × 72 = 12 people.

Answer: (a) \(x = 30\) (b) \(12\)

6.2 Statistical measures questions

Revise it first: Statistical measures notes and worked example.

Question 4 · 3 marks · grade 1

Here are five numbers: \(4, \ 7, \ 7, \ 9, \ 13\)

Find (a) the mode (b) the median (c) the range.

Show the answer, mark scheme and worked solution
  • B1 (a) 7
  • B1 (b) 7
  • B1 (c) 9
  1. (a) 7 appears most often.
  2. (b) The middle (3rd) value is 7.
  3. (c) 13 − 4 = 9.

Answer: (a) \(7\) (b) \(7\) (c) \(9\)

Question 5 · 4 marks · grade 4

The heights, \(h\) cm, of 25 plants are grouped:

\(150 \lt h \le 155\): 3, \(155 \lt h \le 160\): 8, \(160 \lt h \le 165\): 10, \(165 \lt h \le 170\): 4

(a) Work out an estimate for the mean height.

(b) Explain why your answer is only an estimate.

Show the answer, mark scheme and worked solution
  • M1 (a) for midpoints 152.5, 157.5, 162.5, 167.5
  • M1 (a) for 4012.5 ÷ 25
  • A1 (a) 160.5 cm
  • B1 (b) the exact heights are not known; midpoints are used oe
  1. (a) 152.5×3 + 157.5×8 + 162.5×10 + 167.5×4 = 457.5 + 1260 + 1625 + 670 = 4012.5.
  2. 4012.5 ÷ 25 = 160.5 cm.
  3. (b) We only know which class each height is in, so we assume each is at the midpoint.

Answer: (a) \(160.5\) cm (b) the exact heights are not known, so the midpoints are used

Question 6 · 3 marks · grade 5

In a class, the mean score of 12 boys in a quiz is 15 and the mean score of 18 girls is 20.

Work out the mean score of the whole class.

Show the answer, mark scheme and worked solution
  • M1 for 12 × 15 (= 180) or 18 × 20 (= 360)
  • M1 for (180 + 360) ÷ 30
  • A1 18
  1. Boys' total: 12 × 15 = 180. Girls' total: 18 × 20 = 360.
  2. Class mean = 540 ÷ 30 = 18.

Answer: \(18\)

6.3 Probability questions

Revise it first: Probability notes and worked example.

Question 7 · 2 marks · grade 1

A fair six-sided dice is rolled once.

Find the probability of rolling (a) a 5 (b) an even number.

Show the answer, mark scheme and worked solution
  • B1 (a) 1/6
  • B1 (b) 1/2 oe
  1. (a) One outcome out of six equally likely outcomes.
  2. (b) 2, 4 and 6 are even: 3/6 = 1/2.

Answer: (a) \(\frac{1}{6}\) (b) \(\frac{1}{2}\)

Question 8 · 3 marks · grade 4

A spinner can land on red, blue, green or yellow. The probabilities are: red 0.3, blue 0.25, green \(x\), yellow \(2x\).

(a) Work out the value of \(x\).

(b) Find the probability that the spinner lands on red or blue.

Show the answer, mark scheme and worked solution
  • M1 (a) for 0.3 + 0.25 + x + 2x = 1
  • A1 (a) 0.15
  • B1 (b) 0.55
  1. (a) The probabilities add up to 1: 0.55 + 3x = 1, so 3x = 0.45 and x = 0.15.
  2. (b) The outcomes are mutually exclusive, so add: 0.3 + 0.25 = 0.55.

Answer: (a) \(x = 0.15\) (b) \(0.55\)

Question 9 · 4 marks · grade 5

30 people were asked whether they like apples (\(A\)) and whether they like bananas (\(B\)). 16 like apples, 12 like bananas and 6 like neither.

(a) How many people like both?

(b) One of the people is chosen at random. Find the probability that they like exactly one of the two fruits.

Show the answer, mark scheme and worked solution
  • M1 (a) for 30 − 6 = 24 like at least one
  • A1 (a) 4
  • M1 (b) for 12 + 8 (= 20) or 24 − 4
  • A1 (b) 2/3 oe, e.g. 20/30
  1. (a) 30 − 6 = 24 like at least one fruit. 16 + 12 = 28, which counts the people who like both twice: 28 − 24 = 4 like both.
  2. (b) Apples only: 16 − 4 = 12. Bananas only: 12 − 4 = 8.
  3. Exactly one: 20 out of 30 = 2/3.

Answer: (a) \(4\) (b) \(\frac{2}{3}\)

Every question here is original, written for IGCSE Math Revision rather than copied from Pearson papers, and each answer was re-solved independently before publishing.

Topic list for Edexcel IGCSE Maths 4MA1 Foundation statistics and probability: graphical representation of data, statistical measures, probability
The 3 Foundation sub-topics of statistics and probability.

Practise statistics and probability